Converting String to Int in Java using Arrays

Question

I'm trying to convert the string values to integers, however whenever i do this, it gives me the ASCI value of the character instead of the actual typed string.

Example:

a user inputs "11101" on there keyboard to a string variable named binary

for(int i = 0; i < binary.length(); i++){
storage[i] = Integer.valueOf(binary.charAt(i));
}

if I look at the values of storage[i], i will see only the ASCI values of the numbers, and not the actual 1's or 0's

Why? You don't need an array to store an integer.

user207421
– user207421

2013-12-03 22:59:18 +00:00
Commented Dec 3, 2013 at 22:59 — user207421
– user207421, Commented Dec 3, 2013 at 22:59

KV Prajapati · Accepted Answer · 2012-01-03 03:13:01Z

3

Use Integer.parseInt(str,radix) method.

int no=Integer.parseInt("11101",2);

//or

int no=Integer.parseInt("11101");

edited Jan 3, 2012 at 3:13

answered Jan 3, 2012 at 3:05

KV Prajapati

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1 Comment

Android Student Over a year ago

I never knew about the radix before, thank you so much. I will get a great deal of use from this.

Wilmer · Accepted Answer · 2012-01-03 03:10:26Z

2

Try this:

for(int i = 0; i < binary.length(); i++){
    storage[i] = Integer.valueOf(binary.substring(i, i + 1));
}

answered Jan 3, 2012 at 3:10

Wilmer

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Comments

Dennis · Accepted Answer · 2012-01-03 03:06:54Z

2

This should do the trick.

storage[i] = Integer.parseInt( binary.charAt(i));

answered Jan 3, 2012 at 3:06

Dennis

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4 Comments

PlexQ Over a year ago

Except it will not fail on invalid input such as: 110011911

Android Student Over a year ago

Thank you for the example, i had actually tried this one, but still got the same results, but thanks for the info :)

Dennis Over a year ago

@PlexQ there was no mention of validation

Android Student Over a year ago

It returns the asci value of the input, not the typed value

PlexQ · Accepted Answer · 2012-01-03 03:10:10Z

2

for(int i = 0; i < binary.length(); i++){
  storage[i] = Integer.parseInt(binary.charAt(i), 2);
}

answered Jan 3, 2012 at 3:10

PlexQ

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Comments

dansalmo · Accepted Answer · 2013-12-03 22:25:12Z

0

for(int i = 0; i < binary.length(); i++){
    storage[i] = binary.charAt(i) - '0';
}

answered Dec 3, 2013 at 22:25

dansalmo

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