Python Proxy Error With Requests Library

Question

I am trying to access the web via a proxy server in Python. I am using the requests library and I am having an issue with authenticating my proxy as the proxy I am using requires a password.

proxyDict = { 
          'http'  : 'username:[email protected]', 
          'https' : 'username:[email protected]'
        }
r = requests.get("http://www.google.com", proxies=proxyDict)

I am getting the following error:

Traceback (most recent call last):
File "<pyshell#13>", line 1, in <module>
r = requests.get("http://www.google.com", proxies=proxyDict)
File "C:\Python27\lib\site-packages\requests\api.py", line 78, in get
:param url: URL for the new :class:`Request` object.
File "C:\Python27\lib\site-packages\requests\api.py", line 65, in request
"""Sends a POST request. Returns :class:`Response` object.
File "C:\Python27\lib\site-packages\requests\sessions.py", line 187, in request
def head(self, url, **kwargs):
File "C:\Python27\lib\site-packages\requests\models.py", line 407, in send
"""
File "C:\Python27\lib\site-packages\requests\packages\urllib3\poolmanager.py", line     127, in proxy_from_url
File "C:\Python27\lib\site-packages\requests\packages\urllib3\connectionpool.py", line    521, in connection_from_url
File "C:\Python27\lib\site-packages\requests\packages\urllib3\connectionpool.py", line 497, in get_host
ValueError: invalid literal for int() with base 10: '[email protected]'

How do I solve this?

Thanks in advance for your help.

It's good manners to mark correct answers as correct

Sheena
– Sheena

2013-08-26 11:40:07 +00:00
Commented Aug 26, 2013 at 11:40 — Sheena
– Sheena, Commented Aug 26, 2013 at 11:40

guillermooo · Accepted Answer · 2012-01-25 11:04:45Z

17

You should remove the embedded username and password from proxyDict, and use the auth parameter instead.

import requests
from requests.auth import HTTPProxyAuth

proxyDict = { 
          'http'  : '77.75.105.165', 
          'https' : '77.75.105.165'
        }
auth = HTTPProxyAuth('username', 'mypassword')

r = requests.get("http://www.google.com", proxies=proxyDict, auth=auth)

edited Jan 25, 2012 at 11:04

guillermooo

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answered Jan 14, 2012 at 13:52

reclosedev

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9 Comments

Mark Collier Over a year ago

Thanks, I tried that and it solved the error but it still isn't connecting to the proxy. When I look at the returned headers (r.headers), one of them is 'proxy-connection': 'close', which seems to mean its taking too long to connect to the proxy, is there a way to authenticate before requesting any URLs?

reclosedev Over a year ago

@MarkCollier, please try code from edited answer. It was error In first version. Added HTTPProxyAuth, now it should work.

Mark Collier Over a year ago

from requests.auth import HTTPProxyAuth Traceback (most recent call last): File "<pyshell#8>", line 1, in <module> from requests.auth import HTTPProxyAuth ImportError: cannot import name HTTPProxyAuth

reclosedev Over a year ago

@MarkCollier, upgrade requests: pip install --upgrade requests

reclosedev Over a year ago

@MarkCollier, you mean proxy connection error, or cannot import name? I've tested this code on local proxy server and it works. When i'm entering wrong username or password, r.status_code is 407. What is yours?

|

Sean · Accepted Answer · 2014-04-24 10:39:19Z

3

I've been having a similar problem on Windows and found the only way to get requests to work was to set the proxies as environment variables before I started Python. For you this would be something like this:

set HTTP_PROXY=http://77.75.105.165
set HTTPS_PROXY=https://77.75.105.165

You might also want to check is there's a specific port required, and if so set it after the url. For example, if the port is 8443 then do:

set HTTP_PROXY=http://77.75.105.165:8443
set HTTPS_PROXY=https://77.75.105.165:8443

answered Apr 24, 2014 at 10:39

Sean

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1 Comment

raphael Over a year ago

see also stackoverflow.com/questions/5971312/…

Elliott · Accepted Answer · 2019-09-04 00:54:29Z

1

You can use urllib library for this.

from urllib import request
request.urlopen("your URL", proxies=request.getproxies())

edited Sep 4, 2019 at 0:54

Elliott

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answered Apr 16, 2014 at 7:15

Amit Sharma

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