php refering to a variable from string

Question

I'm trying to refer to a variable that's made up from a string, so say $type = "pistol", then:

if ($number > $($type. "s_XP"))

would be

if ($number > $pistols_XP)

Obviously the top one isnt correct syntax, because I don't know how it should be written. Any help?

user142162 · Accepted Answer · 2012-01-22 03:49:02Z

2

The correct syntax would be:

if ($number > ${$type . "s_XP"})

However, you should be storing this data in an object instead (or perhaps an array):

$pistol = new Weapon(50);
$nuke = new Weapon(9001);

$type = $pistol;

if($number > $type->XP)

answered Jan 22, 2012 at 3:49

user142162

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2 Comments

Also: $var = $type . "s_XP"; if( $number > $$var ) ...

$type is actually pulled from a database as $rs[type], just simplified it for the question. thanks

Lightness Races in Orbit · Accepted Answer · 2012-01-22 03:49:29Z

1

Close.

if ($number > ${$type."s_XP"})

But you should be using arrays instead.

answered Jan 22, 2012 at 3:49

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Your Common Sense · Accepted Answer · 2012-01-22 03:51:18Z

1

Correct syntax:

if ($number > $data["pistol"]["xp"])

learn to use arrays

answered Jan 22, 2012 at 3:51

Your Common Sense

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