Comma-separated string to NSArray in Objective-C

Question

So I have no experience with arrays... But I need to use one to populate a UIPickerView. I am obtaining a list of objects via HTTP (NSURLConnection). This works fine. Currently, the response is stored in a NSString as a comma-separated list. I need to convert it to an array. I think this is the type of array I need:

NSArray  * myArray2 = [NSArray arrayWithObjects:@"foo",@"bar",@"baz",nil];

Maybe I'm overcomplicating things... I'm really not sure. There is already an array for the PickerView, and I have it setup so to add an item to the PickerView array I use this code:

[pickerArray addObject:@"Item 1"];

So... How do I separate the items in a comma-separated string (item 1,item 2,item 3,...) into separate array items ([pickerArray addObject:@"item 1"];)??

Andrew Madsen · Accepted Answer · 2012-01-29 23:08:32Z

141

Assuming there's no worry about escaping/unescaping commas contained within the strings, it should be this simple:

NSArray *items = [theString componentsSeparatedByString:@","];

answered Jan 29, 2012 at 23:08

Andrew Madsen

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6 Comments

whitebreadb Over a year ago

So that code will create an array from the comma-separated string?

Andrew Madsen Over a year ago

Yes, as explained in the documentation for NSString: developer.apple.com/library/mac/#documentation/Cocoa/Reference/…

Rick van der Linde Over a year ago

It's late atm and I forgot about this method, it always makes me wonder why some answers aren't chosen as the correct answer.

Andrew Madsen Over a year ago

@RickvanderLinde I think especially with inexperienced StackOverflow users, they just don't know or forget that they should accept an answer to their question. Oh well...

marciokoko Over a year ago

How would I take a comma separated value NSString = "15.009483, -87.485195" and separate them into coordinate values to plot?

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Harikant Amipara · Accepted Answer · 2019-01-11 09:06:13Z

0

Objective-C

NSString *list = @"Karin, Carrie, David";
NSArray *listItems = [list componentsSeparatedByString:@", "];

answered Jan 11, 2019 at 9:06

Harikant Amipara

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