Turning String textfile into object array

Question

I want to use a textfile and take each line and put it into an classobject array. This is my code

try {
    // Open the file that is the first
    // command line parameter
    FileInputStream fstream = new FileInputStream("Patient.txt");
    BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
    String strLine;
    // Read file line by line
    while ((strLine = br.readLine()) != null) {
        // Print the content on the console
        System.out.println (strLine);
    }
    // Close the input stream
    in.close();
} catch (Exception e) { // Catch exception if any
    System.err.println("Error: " + e.getMessage());
}

I need to transform this into an array object and this is how i want it to look like

Patient1 p[] = new Patient1[5];
p[0] = 001, "John", 17, 100, 65, 110, 110, 110, 109, 111, 114, 113, "Swaying, Nausea";
p[1] = 002, "Sun Min", 18, 101, 70, 113, 113, 110, 119, 111, 114, 113, "None";

and so on.

And I want a pony. Seriously though, you need to tell us what you've tried and then ask a specific question. — Hovercraft Full Of Eels
– Hovercraft Full Of Eels, Commented Feb 1, 2012 at 3:45

Makoto · Accepted Answer · 2012-02-01 03:58:51Z

1

Building off of what AVD had suggested, you can accomplish what you want with a constructor that took in your values - although it's not suggested to use too many parameters in a constructor (for readability and debugging's sake). Depending on the way your data is ordered and read, you could even use String.split to get everything into one type (i.e. String).

public class Patient {

   public Patient(String name, String id, String symptoms, String measurements) {  to get the individual fields from using a delimiter.

        // Stuff to fill in the fields goes here
    }
}

You would invoke this by using the call new Patient("John, "001", "Swaying, Nausea", ...). Again, this depends on how you read the data coming in; if you cannot bunch the data up in a reasonable way, then you could also opt to create accessors and mutators.

answered Feb 1, 2012 at 3:58

Makoto

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3 Comments

user1181810 Over a year ago

public Patient1(int i,String n, int a, double w, int h,int bp1, int bp2, int bp3, int bp4, int bp5, int bp6, int bp7, String s){ id = i; name = n; age = a; weight = w; height = h; BP1 = bp1; BP2 = bp2; BP3 = bp3; BP4 = bp4; BP5 = bp5; BP6 = bp6; BP7 = bp7; SYM = s; What do I do now?

user1181810 Over a year ago

Can I identify each line by an array number?

Makoto Over a year ago

@user1181810, you could edit your question to include what you've tried so far; it'll be far easier to read. As for identifying each line by an array number, I'm afraid I don't understand what you mean by this. If you store each Patient object into an array or ArrayList, you'll be able to get them back in the order that they came in. (You can extend toString() and return the values of each object if you want.) If you're still unsure, update your question to clarify your intent.

KV Prajapati · Accepted Answer · 2012-02-01 03:46:27Z

0

You have to create Patient class with 13 fields, constructors and setter/getter.

public class Patient
{
   private String field1;
   private String field2; 
   private int field3;
   ....
   public void setField1(String field1) { this.field1=field1; }
   public String getField1() { return field1;}
   ...   
}

and use ArrayList<Patient> instead of array.

ArrayList<Patient> patients=new ArrayList<Patient>();
Patient pat=new Patient();
//set value to the patient object
patients.add(pat);

answered Feb 1, 2012 at 3:46

KV Prajapati

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1 Comment

user1181810 Over a year ago

I have 13 methods like getID() and getName() how can I connect the string with the right method?

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