Uncaught SyntaxError: Unexpected end of input - Javascript error

Question

I get this error when i try to call this function in Chrome 16.0.912.77 m:

function fade(e){
    if(op > 0){
        op -= 0.01;
        document.getElementById(e).style.opacity = op;
        window.setTimeout("fade(\""+e+")\"", 10);
    }
}

It's a simple function which fade a element on my page out. I read that the error appears when i forgett a }-bracket, but i closed all..

Any ideas?

and if you do setTimeout(function() { fade(e) },10);instead? — mplungjan
– mplungjan, Commented Feb 1, 2012 at 9:06
As an aside, you should avoid passing a string to setTimeout since it is a form of eval. See window.setTimeout at MDN for more. — Cheran Shunmugavel
– Cheran Shunmugavel, Commented Feb 1, 2012 at 9:09

Cheran Shunmugavel · Accepted Answer · 2012-02-01 08:59:24Z

2

window.setTimeout("fade(\""+e+"\")", 10);

You have the closing quote and closing parentheses swapped.

answered Feb 1, 2012 at 8:59

Cheran Shunmugavel

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1 Comment

Nice18 Over a year ago

Better code: setTimeout(() => fade(`"${e}"`), 10);

Álvaro González · Accepted Answer · 2012-02-01 09:08:17Z

1

If you inspect this in your favourite JavaScript console:

var e = "foo";
alert("fade(\""+e+")\"");

... you'll see this:

fade("foo)"

Use on your favour the fact that JavaScript allows both single and double quotes:

var e = "foo";
alert('fade("' + e+ '")');

Or, even better, call setTimeout() with a function reference instead of a string (find some examples in the linked page).

answered Feb 1, 2012 at 9:08

Álvaro González

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