How do I extract the "program name" from a string. The string will look like this :
% O0033(SUB RAD MSD 50R III) G91G1X-6.4Z-2.F500 G3I6.4Z-8. G3I6.4 G3R3.2X6.4F500 G91G0Z5. G91G1X-10.4 G3I10.4 G3R5.2X10.4 G90G0Z2. M99 %
The program name is (SUB RAD MSD 50R III). Storing the result in another string is fine. I'm learning powershell so any explaination of your answers will be appreciated.
The following regex extract anything between the parenthesis:
PS> $prog = [regex]::match($s,'\(([^\)]+)\)').Groups[1].Value
PS> $prog
SUB RAD MSD 50R III
Explanation (created with RegexBuddy)
Match the character '(' literally «\(»
Match the regular expression below and capture its match into backreference number 1 «([^\)]+)»
Match any character that is NOT a ) character «[^\)]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character ')' literally «\)»
Further Reading:
If program name is always the first thing in (), and doesn't contain other )s than the one at end, then $yourstring -match "[(][^)]+[)]" does the matching, result will be in $Matches[0]
-match returns a boolean, you probably want something like if($something -match "regexp") { $Matches[0] } else { '' } in an expression context.Just to add a non-regex solution:
'(' + $myString.Split('()')[1] + ')'
This splits the string at the parentheses and takes the string from the array with the program name in it.
If you don't need the parentheses, just use:
$myString.Split('()')[1]
Using -replace
$string = '% O0033(SUB RAD MSD 50R III) G91G1X-6.4Z-2.F500 G3I6.4Z-8.G3I6.4 G3R3.2X6.4F500 G91G0Z5. G91G1X-10.4 G3I10.4 G3R5.2X10.4 G90G0Z2. M99 %'
$program = $string -replace '^%\sO\d{4}\((.+?)\).+$','$1'
$program
SUB RAD MSD 50R III
