making separate array from existing json django

Question

I have this array of JSON:

[{'pk': 4L, 'model': u'logic.member', 'fields': {'profile': 3L, 'name': u'1', 'title': u'Mr', 'dob': datetime.date(1983, 1, 1), 'lastname': u'jkjk', 'redressno': u'jdsfsfkj', 'gender': u'm'}}, {'pk': 5L, 'model': u'logic.member', 'fields': {'profile': 3L, 'name': u'2', 'title': u'Mr', 'dob': datetime.date(1983, 1, 1), 'lastname': u'jkjk', 'redressno': u'jdsfsfkj', 'gender': u'm'}}]

I want to make separate array of JSON for only fields property.

What I tried is:

memarr=[] 

       for index,a in data1:
          print index
          print a
          memarr[index]=a[index].fields

And it is giving an error of:

too many values to unpack

Please correct.

Yuji 'Tomita' Tomita · Accepted Answer · 2012-02-04 11:34:12Z

2

First of all, data1 is a list, so you can't unpack it into 2 variables.

If you want the index, you have to use something like enumerate.

Second, you can't assign to a list via indexing if the key doesn't exist. You have to append or use another valid list insert method.

Third, a[index].fields doesn't really make sense - there is no key in a that would be associated with an integer index and fields is not an attribute.

You're probably looking for something like this:

memarr = []
for index, a in enumerate(data1):
    memarr.append(a['fields'])

answered Feb 4, 2012 at 11:34

Yuji 'Tomita' Tomita

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Daniel Roseman · Accepted Answer · 2012-02-04 11:34:53Z

0

So many things wrong with that snippet...

Anyway:

memarr = [a['fields'] for a in data]

answered Feb 4, 2012 at 11:34

Daniel Roseman

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