PHP : Cannot assign an Object to array

Question

I have create the following class :

Main class file

class NativeTabs
{
    private $tabs = array();

    public function __construct()
    {
        require_once('/options_elements.php');
    }

    public function add_tab($key = '', $name = '')
    {
        // ...

        $this->tabs[$key] = $name;
        $this->tabs[$key][] = new OptionsElements();

        // ...

    }
}

$nt = new NativeTabs();
$nt->add_tab('tabname', "Tab Name");

options_elements.php File

class OptionsElements
{
    public function __construct()
    {
    }
}

And when I execute that code I get the following error :

Fatal error: [] operator not supported for strings in PATH/TO/MY/FILEnative_tabs.php on line THE_LINE_THAT_CONTAIN_THE_CODE($this->tabs[$key][] = new OptionsElements();)

Why I can't assing the object in $this->tabs[$key][] ?

Any idea please ?

Why you put require_once statement in NativeTabs constructor? — Shiplu Mokaddim
– Shiplu Mokaddim, Commented Feb 28, 2012 at 10:19

Nicola Peluchetti · Accepted Answer · 2012-02-28 10:05:26Z

2

You should do

$this->tabs[$key] = array();
 $this->tabs[$key][] = new OptionsElements();

otherwise you use [] with a string (you assigned $this->tabs[$key] = $name; on the line above so $this->tabs[$key] is a string)

answered Feb 28, 2012 at 10:05

Nicola Peluchetti

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Comments

Matthieu Napoli · Accepted Answer · 2012-02-28 10:08:59Z

2

$this->tabs[$key] is a string, not an array.

You can't add an item to a string as if it was an array.

answered Feb 28, 2012 at 10:08

Matthieu Napoli

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Comments

Till Helge · Accepted Answer · 2012-02-28 10:05:19Z

1

Why should you be able to assign that?

$this->tabs[$key] = $name;

Judging by the name you just set the array element to a string. Then you try to append an array element to this string? That won't work.

answered Feb 28, 2012 at 10:05

Till Helge

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Starx · Accepted Answer · 2012-02-28 10:11:59Z

1

This will work without errors.

$this->tabs[$key] = array("name");
$this->tabs[$key][] = new OptionsElements();

answered Feb 28, 2012 at 10:11

Starx

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Shiplu Mokaddim · Accepted Answer · 2012-02-28 10:19:13Z

1

See inline.

$this->tabs[$key] = $name;
// $this->tabs[$key] becomes a string that contains $name
$this->tabs[$key][] = new OptionsElements();
// $this->tabs[$key][] has no meaning here as its neither array nor an unset value. 
// if it was unset or not declared PHP would have make it an array.

You could you the following.

$this->tabs[$key]['name'] = $name;
$this->tabs[$key]['option_elements'] = new OptionsElements();

edited Feb 28, 2012 at 10:19

answered Feb 28, 2012 at 10:13

Shiplu Mokaddim

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