I'm a beginner in C and am having some trouble with structures in C. Here is my code;
#include <stdlib.h>
#include <stdio.h>
#include <conio.h>
struct rec
{
char i;
char b;
char j;
} ;
int main()
{
struct rec *p;
p=(struct rec *) malloc (sizeof(struct rec));
(*p).i='hello';
(*p).b='world';
(*p).j ='there';
printf("%c %c %c\n",(*p).i,(*p).b,(*p).j);
free(p);
getch();
return 0;
}
The out of this is; o d e
How can I pass in the whole word, rather than just one letter.
Define the structure members as char *:
struct rec
{
char *i;
char *b;
char *j;
} ;
and use printf with %s:
printf("%s %s %s\n",(*p).i,(*p).b,(*p).j);
Also, you need to replace ' with ": (*p).j ="there"; and if you assign string literals (which may not be modified), change the struct members to const:
struct rec
{
const char *i;
const char *b;
const char *j;
} ;
const char * based on the original code sample.The common string type in C is char*, which means a pointer to an array of char elements. C marks the end of a string with a special character \0. Those strings are generally called 0-terminated strings.
To save one in your structure you need something like this:
struct foo {
char* words;
};
Character literals (a.k.a inline strings) have the type const
char[n] where n is the length of the string plus one element for
the null-terminator, so you cannot assign a character literal to a
char*. You will need to allocate strlen(x) + 1 char elements and
then copy the contents of the string literal into this memory. Don't
forget to free it.
Maybe you should attempt to understand pointers and arrays first.
