I need extract only "40:37.298s" from:
Total time: 40:37.298s
using JS, but I`m new in JS, can some one help?
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7 Answers
> 'Total time: 40:37.298s'.substr(12)
'40:37.298s'
If you want to use a regex for more flexibility:
> /([0-9]+:[0-9]+\.[0-9]+s)/.exec('Total time: 40:37.298s')[1]
'40:37.298s'
Comments
There are many ways to do this. Here's one:
var str = "Total time: 40:37.298s";
str.split(": ")[1]
In most cases I prefer splitting on some known pivot, rather than trying to extract a specific substring (as others have shown) for the following reasons:
- It's more flexible; this will still work if the first part of the string contains slight variations (but the substring method won't)
- It's easier to see what's being extracted (but the substring method requires that I manually count positions in the string to verify that I'm selecting the right thing)
Comments
var time = 'Total time: 40:37.298s';
time = time.match(/\d{1,2}:\d{1,2}\.\d+s/);
Comments
the substring method is what you're looking for:
"Total time: 40:37.298s".substring("Total time: ".length);
Comments
var result = "Total time: 40:37.298s".replace(/^.*([0-9]{2}:[0-9]{2}\.[0-9]{3}s)/g,'$1')
Comments
var item = 'Total time: 40:37.298s';
var pattern = /\d{1,2}\:\d{2}\.\d{3}s/g;
var res = pattern.exec(item);
That is:
- \d{1,2} one or two digits
- \: the ':' char
- \d{2} two digits
- . the '.' char
- \d{3} three digits
- s the 's' char
1 Comment
Petr Vostrel
Note, that Regexp
.exec() will assign matches in an Array to the res, so to get the actual matched value from the code above, you'll need to query res[0].I would say use a RegEx like [:\.0-9]*s
for example
yourText.match("regex")
in your case it will be
"Total time: 40:37.298s".match("[:\.0-9]*s")[0]
It will return 40:37.298s
