jQuery ajax fetch data from PHP into a jQuery variable

Question

I need to receive the status of vote using ajax and php and jquery. Following is my code :

var VoteStatus= GetStatus() ;
var ID = $('#ID').val();

function GetStatus() {
    var res = '';

    $.ajax({
        type: "POST",
        data: {VoteID:ID} ,
        url: "/vote_status.php",
        async: false,       
        success: function(result) { res=result; } 
    });                  

    return res;
}

alert('Vote Status= ' + VoteStatus);

In my php file:

$VoteID = $_POST['VoteID'];
$Property = $_POST['Property'];



if ( $VoteID == 0 ) 
    echo 'No Vote provided - Property = '. $Property;

exit;

The alert box shows: Vote Status = No Vote Provided

Please help.

I have posted the VoteID, but the php file doesn't seem to receive it.

If the alert box says "No vote provided, then your php script should be working well. Check what this line var ID = $('#ID').val(); returns. — Chibuzo
– Chibuzo, Commented May 20, 2012 at 9:19
possible duplicate of How can I use AJAX to fetch data and store it in javascript variables? - and the many, many, many, many, many, many, many, many others: stackoverflow.com/… — hakre
– hakre, Commented May 20, 2012 at 9:29

coolguy · Accepted Answer · 2012-05-20 09:36:12Z

2

Try the alert in here and check if its working

 $.ajax({
        type: "POST",
        data: {"VoteID":ID} ,
        url: "/vote_status.php",
        async: false,       
        success: function(result) { 
  alert(result); } 
    });

answered May 20, 2012 at 9:36

coolguy

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5 Comments

sqlchild Over a year ago

Dear sir , the alert box shows this : "Vote Status = No Vote Provided - Property = undefined "

coolguy Over a year ago

Are you getting the ID correctly execute this line and check if its not zero alert($('#ID').val());

sqlchild Over a year ago

yes I am getting and its non zero , i mean am getting the correct value

coolguy Over a year ago

Do you provided quotes for VoteID ? "VoteID"

coolguy Over a year ago

IF you are using Firefox with firebug..just make this code change in the php file and see if its non-zero echo $_POST['VoteID'];exit; and look on your console for result

msgmash.com · Accepted Answer · 2012-05-20 09:22:36Z

2

The name of the POST variable needs to be in quotes, as in

data: {"VoteID":ID}

answered May 20, 2012 at 9:22

msgmash.com

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3 Comments

sqlchild Over a year ago

data: {"VoteID":ID , "Property":prop} --- the property is shown as undefined in the alert box

hakre Over a year ago

@sqlchild: Please learn what json is. api.jquery.com/jQuery.ajax ; php.net/json

sqlchild Over a year ago

sir, what's the error in my code ? there's nothing but still its not working

Justin John · Accepted Answer · 2012-05-20 09:40:30Z

2

Try this and check jquery ajax manuals

$.ajax({
    type: "POST",        
    data:"VoteID=" + ID +"&secondparam=" + secondvalue,
    url: "/vote_status.php",
    async: false,       
    success: function(result) { alert(result); } 
});

answered May 20, 2012 at 9:40

Justin John

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1 Comment

coolguy Over a year ago

THis is GET method ..so you need to change the type attribute to "GET"

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