Dynamic text fields values into PHP array

Question

I have a dynamic web form that creates text after the user tells it how many he wants, what I want to do, is to get the info of those text fields into the next form, I've read a question that is
pretty much what I want to do;
But I haven't had any luck so far;

for ($i = 1; $i <= $quantity; $i++) {
echo "<input type='text' class='text' name='classEmpleado[]' id='empleado$i' />";}

When I try to retrieve them I use this;

$empleado[] = $_POST['classEmpleado[]'];
$i = 0;    
for ($i = 1; $i <= $quantity; $i++) {
echo "$empleado[$i]<BR><BR>";
}

But I get the error Undefined index: classEmpleado[] What am I doing wrong?

ANSWERED! For anyone looking for the same thing, look at the response of Sherbrow, And you would just have to edit the loop to this

$empleado[] = $_POST['classEmpleado[]'];
$i = 0;    
for ($i = 0; $i < $quantity; $i++) {
echo "$empleado[$i]<BR><BR>";
}

Sherbrow · Accepted Answer · 2012-08-02 14:17:51Z

0

If $empleado is not previously declared or just empty, you are looking for that

$empleado = $_POST['classEmpleado']

But if $empleado is an array, and contains data, you may want to merge everything in one only array

$empleado = array_merge($empleado, $_POST['classEmpleado']);

Whichever way you choose, there should be a check to be certain that $_POST['classEmpleado'] is defined and is an array. Something like :

if(isset($_POST['classEmpleado']) && is_array($_POST['classEmpleado'])) {
    /* ... */
}

answered Aug 2, 2012 at 14:17

Sherbrow

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Comments

Dunhamzzz · Accepted Answer · 2012-08-02 14:10:42Z

0

Try $empleado[] = $_POST['classEmpleado'];

When you put name[] at the end of the fieldname, it will be passed to PHP as an array in $_POST with the key of name like so: $_POST['name'] = array(1,2,3,4);

answered Aug 2, 2012 at 14:10

Dunhamzzz

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1 Comment

enrique.ortsa Over a year ago

That worked like a charm, thanks, but I had to write it likeSherbrow explained in the answer below, $empleado = $POST['classEmpleado'];

Bilel Chihi · Accepted Answer · 2012-08-02 14:22:49Z

-1

This statement here is wrong ($empleado[] = $_POST['classEmpleado[]'])

If you want to access $_POST the input field named classEmpleado[], you have to do so :

for($i=0; $i<count($_POST['classEmpleado']); $i++)
{
    echo $_POST['classEmpleado'][$i] . '<br /><br />';
}

answered Aug 2, 2012 at 14:22

Bilel Chihi

1

3 Comments

Bilel Chihi Over a year ago

This will be the structure of $_POST array :

Array (     [classEmpleado] => Array         (             [0] => Some text 0             [1] => Some text 1             [2] => Some text 2         ) )

enrique.ortsa Over a year ago

Thanks for your response, I'll try this in another web form that I intend on making, appreciated!

Dunhamzzz Over a year ago

You shouldn't put count() inside the loop condition, it will get executed EVERY iteration of the loop.

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