Bash Script - Scope of variables in while loop [duplicate]

Question

Possible Duplicate:
Bash Script - Variable Scope in Do-While loop

In the following code, it prints the correct value of i in inner while loop, but it prints 0 after it comes out of inner while loop:

string="Medicine"
for file in *
do
    i=0
    cat $file | while read line
    do
        echo $line
        if [ "$line" == "$string" ];
        then
            i=`expr $i + 1`
            echo $i
        fi
    done
    echo $i
done

Sreejith B Naick · Accepted Answer · 2012-10-03 05:45:30Z

-2

By default variables have global scope in shell scripting, which make "i " global. if you want to make a variable as local ,use keyword "local" , for eg: local i=0

for more details check the link, http://www.bashguru.com/2008/06/bash-variables-scope.html

answered Oct 3, 2012 at 5:45

Sreejith B Naick

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1 Comment

chepner Over a year ago

It is an error to use local outside a function, and you completely ignore the fact that the while loop is running in a subshell, which is the source of the poster's problem.

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