How to call JavaScript function in "php" inputbox in echo on "onChange" event

Question

javascript function which is used in OnChange event

function calc(A,B,SUM) { 
    var one = Number(A); 
    if (isNaN(one)) { alert('Invalid entry: '+A); one=0; } 
    var two = Number(document.getElementById(B).value);  
    if (isNaN(two)) { alert('Invalid entry: '+B); two=0; } 
    document.getElementById(SUM).value = parseInt(one) + parseInt(two);
}

I have forloop for create 10 input fox

Input boxes

<?php
for($k=1;$k<=$textboxindex;$k++)
{
    echo "<input type=\"text\" class='textboxsizeqty' name=\"qty[]\" value=\"$qty\" id         ='op1' onChange=\"calc('this.value','op2','result');\"/>";
    echo "<br/>";
}
?>

Input boxes

<?php
for($k=1;$k<=$textboxindex;$k++)
{
    echo "<input type=\"text\" class='textboxsize' name=\"rate[]\" value=\"$rate\" id      ='op2' onChange=\"calc('this.value','op2','result');\" />";
    echo "<br/>";
}
?>


<?php
for($k=1;$k<=$textboxindex;$k++)
{
    echo "<input type=\"text\" class='textboxsize' name=\"sum[]\" value=\"\"     id='result'/>";
    echo "<br/>";
}
?>

It's doesn't work here what I am doing. I'm New in PHP. Thanks

try it without this.value in parenthesis so remove these: ' — Lennart
– Lennart, Commented Oct 26, 2012 at 20:30

Jericho · Accepted Answer · 2012-10-26 20:33:10Z

0

Please try and why do you give the quotes in this.value.

<?php
for($k=1;$k<=$textboxindex;$k++)
{
echo "<input type=\"text\" class='textboxsizeqty' name=\"qty[]\" value=\"$qty\" id         ='op1' onChange=\"calc(this.value,'op2','result');\"/>";
echo "<br/>";
}
?>

answered Oct 26, 2012 at 20:33

Jericho

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3 Comments

user1778175 Over a year ago

and the sun is not correct like example 5 + 5 = 55 >i dont know how to deal with it. Can you help plz.

Jericho Over a year ago

document.getElementById(SUM).value = parseInt(one) + parseInt(two); --change javascript final line like this .

user1778175 Over a year ago

stackoverflow.com/questions/13145121/…

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