I am not much familiar with java . But I know in php we can do with json_decode function . Is there any particular function in java to decode the below string to an array?
[ {
"type" : "panaroma",
"image" : "http://test.com/images/aneesh/Desktop/19_september/pano-1.png",
"location" : "{{487,393},{197,235}}",
"trigger" : "{{487,393},{197,235}}",
"orientation" : "portrait",
} ]
Look this: http://www.tutorialspoint.com/json/json_java_example.htm
Some like thus:
import org.json.simple.JSONObject;
import org.json.simple.JSONArray;
import org.json.simple.parser.ParseException;
import org.json.simple.parser.JSONParser;
class JsonDecodeDemo
{
public static void main(String[] args)
{
JSONParser parser=new JSONParser();
String s = "[0,{\"1\":{\"2\":{\"3\":{\"4\":[5,{\"6\":7}]}}}}]";
try{
Object obj = parser.parse(s);
JSONArray array = (JSONArray)obj;
System.out.println("The 2nd element of array");
System.out.println(array.get(1));
System.out.println();
JSONObject obj2 = (JSONObject)array.get(1);
System.out.println("Field \"1\"");
System.out.println(obj2.get("1"));
s = "{}";
obj = parser.parse(s);
System.out.println(obj);
s= "[5,]";
obj = parser.parse(s);
System.out.println(obj);
s= "[5,,2]";
obj = parser.parse(s);
System.out.println(obj);
}catch(ParseException pe){
System.out.println("position: " + pe.getPosition());
System.out.println(pe);
}
}
}
JSONObjectinstead ofJSONArraybecause current String containJsonObjectas root element instead ofJsonArray: JSONObject jsonObject = new JSONObject(readlocationFeed);