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Is there a simple, one-line way to get the data of a form as it would be if it was to be submitted in the classic HTML-only way?

For example:

<form>
    <input type="radio" name="foo" value="1" checked="checked" />
    <input type="radio" name="foo" value="0" />
    <input name="bar" value="xxx" />
    <select name="this">
        <option value="hi" selected="selected">Hi</option>
        <option value="ho">Ho</option>
</form>

Output:

{
    "foo": "1",
    "bar": "xxx",
    "this": "hi"
}

Something like this is too simple, since it does not (correctly) include textareas, selects, radio buttons and checkboxes:

$("#form input").each(function () {
    data[theFieldName] = theFieldValue;
});
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33 Answers 33

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2024 solution

Almost answer is correctly. But it take a lot of code, or it does not provide key/value object. Here is mine

const formData = new FormData(document.querySelector('form'));
const data = Object.fromEntries(data.entries());
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Comments

0

You are all not fully correct. You cannot write:

formObj[input.name] = input.value;

Because this way if you have multiselect list - its values will be overwritten with the last one, since it's transmitted as: "param1" : "value1", "param1" : "value2".

So, correct approach is:

if (formData[input.name] === undefined) {
    formData[input.name] = input.value;
}
else {
    var inputFieldArray = $.merge([], $.isArray(formData[input.name]) ? formData[input.name] : [formData[input.name]]);
    $.merge(inputFieldArray, [input.value]);
    formData[input.name] = $.merge([], inputFieldArray);
}

Comments

0

This method should do it. It serializes the form data and then converts them to an object. Takes care of groups of checkboxes as well.

function getFormObj(formId) {
  var formParams = {};
  $('#' + formId)
    .serializeArray()
    .forEach(function(item) {
      if (formParams[item.name]) {
        formParams[item.name] = [formParams[item.name]];
        formParams[item.name].push(item.value)
      } else {
        formParams[item.name] = item.value
      }
    });
  return formParams;
}

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