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Is there a way to achieve the following:

calculate_fun(self.key1="some_value", self.key2="another_value")

Basically use a variable as the key for a Keyword variable.

Currently, if I try this it errors out as it is not accepting a variable on the left hand side of the "=" sign. It is expecting something in the form of:

calculate_fun(field1="some_value", field2="another_value")

But that means that I need to hardcode field1 and field2. I would like the keyword to be a variable so I can change it at runtime, hence field1 can become field55 at runtime.

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  • 1
    Are you serious? The person who answered my question had it exactly right. Commented Jul 2, 2014 at 21:24
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    He only made a wild guess and got it right. But to me what you wrote seems like you wanted to have to automatically perform and assignment to an instance attribute when calling a function, which doesn't make any sense. I downvoted your question because, as it currently stands, it cannot be understood by future readers. I'll lift it when you make the question clearer. Commented Jul 2, 2014 at 21:26
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    @Bakuriu no wild guess, although poorly worded (before the edit), this question does make sense. Commented Jul 2, 2014 at 21:29
  • @StefanoSanfilippo Exactly, in this case it's also a (obvious) duplicate. Commented Jul 2, 2014 at 21:30
  • Clearly a duplicate, but it should be noted that the def f(**kwargs) stated in the accepted answer of the original is not necessary. Commented Jul 2, 2014 at 21:32

1 Answer 1

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Yes, with dictionary unpacking:

calculate_fun(**{self.key1: "some_value", self.key2: "another_value"})
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