when I am compiling this small program I am getting different values as output, instead of getting numbers from 0 to 5. And the size of array is always 8. The different values I am getting are:
-981774704
32767
0
0
4195728
0
Any tips would be really valuable. Thank you
#include <stdio.h>
int main() {
int array[10];
int i;
for (i = 0; i < 6; i++) {
printf("%d\n", array[i]);
}
int z = sizeof(&array);
printf("\n Size of array is %d", z);
return 0;
}
You aren't assigning any values to the array, so you're getting the uninitialized values.
You need to do something like array[0] = 5; //or some value etc.
If you want an array of size 8, with the numbers indexing the array stored in it, so {0, 1, 2, 3, 4, 5, 6, 7}, you could do something like:
int array[8];
for(int i = 0; i < 8; ++i)
{
array[i] = i;
}
the elements of the array are uninitialized therefore it's printing garbage value...first initialize the elements with values...you can do this...
#include<stdio.h>
int main()
{
int array[10] ;
int i;
for (i = 0; i < 6; i++)
{
array[i]=i;
printf("%d\n", array[i]);
}
int z = sizeof(&array);
printf("\n Size of array is %d", z);
return 0;
}
if you want the array to be initialized automatically then declare the array globally...
if you want to get the size of the whole array remove &
sizeof(array);
int z = sizeof(&array); : remove & or int z = sizeof(array)/sizeof(*array); (always 10! LOL)
int array[10]: sizeof(&array) returns the size of a pointer, typical values area 2, 4 or 8. sizeof(array[0]) returns the size of an int whose typical sizes are 2, 4 or8. Pointer size and int size are not specified as needing to be the same in C. They may or may not have the same value. More infoC will not initialize your array to any default value. When you create the array it will be full of garbage values (nothing relevant or defined). Always initialize your data using memset or something equivalnet.
So if you are expecting a value of 0 on a new array then initialize it like this:
memset(array, 0, sizeof(array));
int array[10] = {0};you have to initialize your array first, memory may not be filled with 0 by default
int z = sizeof(&array);returns the size of a pointer, 8 in your case. To get the size of the array, useint z = sizeof array;, which is likely 40 or 80 bytes. To get the number of elements in the array, useint z = sizeof array/sizeof array[0];which is 10. in this case.sizeofoperator to determine the size of the type and size of the object( of the result of the expression). it is not vector#size.