How to run executable with input file using Python?

Question

I am running an executable from cmd:

*.exe input.inp

I want to run it using python and tried following:

os.system('"*.exe"')

But don't know how to specify input file as well. Any suggestions?

possible duplicate of how to execute a python script file with an argument from inside another python script file — Tui Popenoe
– Tui Popenoe, Commented May 6, 2015 at 4:53
Possible duplicate of Using Python to run executable and fill in user input — catsock
– catsock, Commented Sep 26, 2018 at 21:15

Community · Accepted Answer · 2017-05-23 12:28:33Z

1

import os
from subprocess import Popen, PIPE

p = Popen('fortranExecutable', stdin=PIPE) #NOTE: no shell=True here
p.communicate(os.linesep.join(["input 1", "input 2"]))

For more please refer to:

Using Python to run executable and fill in user input

edited May 23, 2017 at 12:28

CommunityBot

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answered May 6, 2015 at 4:52

Abhishek Dey

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Comments

Ibe · Accepted Answer · 2015-05-06 16:49:57Z

0

I had to launch cmd window and specify input file location from within Python script. This page was really helpful in getting it done.

I used Popen(['cmd', '/K', 'command']) from above page and replaced '/K' with '/C' in it to run and close the cmd window.

answered May 6, 2015 at 16:49

Ibe

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Comments

user3376851 · Accepted Answer · 2020-12-10 09:55:25Z

0

import os
os.system(r'pathToExe.exe inputFileOrWhateverOtherCommand')

answered Dec 10, 2020 at 9:55

user3376851

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