python sorting deep in objects

Question

I need some help with sorting in python. I got a data object, in this objects are lists and I like to sort the data for a specific list item. Currently I print it out like this:

 for item in data:
     for proj in item:
         print proj.get('id')

So I want this data already sorted by the 'id' item.

This is how the data object looks like, if I print it:

[[{u'archived': False, u'name': u'someone', u'num_files': 0, u'managed_by': {u'username': u'somebody', u'role': u'somerole', u'email_address': u'me@somewhere', u'id': u'307', u'name': u'firstname lastname'}, u'updated_on': u'2015-06-18 17:55:39', u'id': 23}, 
{u'archived': False, u'name': u'someoneelse', u'num_files': 0, u'managed_by': {u'username': u'somebody else', u'role': u'somerole', u'email_address': u'you@somewhere', u'id': u'341', u'name': u'Firstname Lastname'}, u'updated_on': u'2015-06-09 17:38:52', u'id': 48}]]

Just two lists from the whole, but I like to sort for the last id, in this example 23 and 48

Can you show an example of the data, and an example of it sorted? — Cory Kramer
– Cory Kramer, Commented Jun 19, 2015 at 11:58
just added an data example, if I just use data.sort I get TypeError: 'builtin_function_or_method' object is not iterable — Andreas Hubert
– Andreas Hubert, Commented Jun 19, 2015 at 12:08
Can you give an example which has more than one data object, and each data object has more than one item? What would the output look like if you had two data objects, one that contained ids 42 and 15, and the other containing ids 23 and 8? — Kevin
– Kevin, Commented Jun 19, 2015 at 12:15
The example object has two lists, in reality it hast about 40 lists. I just need the last id as it is an item in that list. The other id in this line belong to another sublist in that list. - by the way, I'm not sure if I'm using the terms for lists objects and items etc correct ... I'm kinda new to python — Andreas Hubert
– Andreas Hubert, Commented Jun 19, 2015 at 12:26

Community · Accepted Answer · 2017-05-23 11:58:31Z

1

Try this:

import numpy as np
data_new = np.array(data).flatten()
sorted_list = sorted(data_new, key=lambda x: x['id'])

First line will create one list of dict. Second will sort them by 'id' key. After that you could print it like you want:

for i in sorted_list:
    print(i['id'])

Edit: Because your list could contain sublists of different sizes (like here) this will broke ndarray.flatten or numpy.ravel, also because your elements are dictionaries np.fromiter will unworkable too. So you should change second line to this:

data_new = np.hstack(data)

edited May 23, 2017 at 11:58

CommunityBot

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answered Jun 19, 2015 at 12:15

user4999547

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2 Comments

Andreas Hubert Over a year ago

what do I have to import for np? Google said "import numpy as np" but I get "ImportError: No module named numpy"

user4999547 Over a year ago

yes, sorry, you should install and import numpy module (it's very usefull and popular).

Andreas Hubert · Accepted Answer · 2015-06-19 13:08:38Z

0

I did a mistake, I used .append with my list to add more entries, instead I should have used .extend Now my list is not that deep anymore and it's all way much easier:

sorted_list = sorted(data, key=lambda x: x['id'])
for item in sorted_list:
    print str(item.get('id')) + " : " + item.get('name')

But thanks for the numpy tip, I think that would be helpful if I reall would search deeper in the objects sublist etc.

answered Jun 19, 2015 at 13:08

Andreas Hubert

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