Displaying an array by using pointer techniques [closed]

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I want to display the contents of an array with type double that has a length of 5 without using the [ ] indexing . I can only use a for loop and pointer techniques.

How can you achieve that ? Can anyone give me a brief explanation of pointers as I have no idea how to use them exactly ?

Have you tried anything or even did a google research? There is a ton of documentation about pointers out there. If you want a detailled answer, please ask a detailed question. See how to ask a question for more :) — Magix
– Magix, Commented Jan 13, 2016 at 20:54
Firstly you should read something about pointers, then you should study pointer arithmetic, that's what you are looking for — Claudio Cortese
– Claudio Cortese, Commented Jan 13, 2016 at 23:59

dbush · Accepted Answer · 2016-01-13 20:57:05Z

2

The array indexing operator is a shorthand for hiding pointer arithmetic.

So if you have an array like this:

double a[5];

Instead of using this expression:

a[1]

You can use this:

*(a + 1)

answered Jan 13, 2016 at 20:57

dbush

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