Changing function's default parameters in Python [duplicate]

Question

Let's say this is the signature of my function:

def foo(x,y,z=0):
.
.

When I want to use this function, how can I override the value of z without changing the function or the signature?

Why would you change z's default value? The reason you change it in the first place is to be default. — Andrew Li
– Andrew Li, Commented Aug 21, 2016 at 13:55
Do you mean how to pass in a value for z when calling the function? — Moon Cheesez
– Moon Cheesez, Commented Aug 21, 2016 at 13:56
You can't. You could assign a new function object to the name foo with a different default that calls the old function object. Would that do? — Martijn Pieters
– Martijn Pieters, Commented Aug 21, 2016 at 13:56

Nidhin Bose J. · Accepted Answer · 2016-08-21 13:56:55Z

5

Just pass value explicitly.

def foo(x, y, z=0):
    print z

foo(1,3)
>> 0 # default value

foo(1,2,5)
>> 5 # new value passed

answered Aug 21, 2016 at 13:56

Nidhin Bose J.

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