As the title says I need help with a bash script that has to generate a string given two numeric variables. That string will be used to generate a file name, but when I test the name generation code it yields nothing
The script is the code that follows
# !usr/bin
set nombre
declare -a i
declare -a j
set $i 1
set $j 2
set nombre "$i\_$j.txt"
echo $i
echo $j
Here is what it yields:
entropy@3PY:~$ ./test4
As you can see it yields nothing while it should yield
1
2
thanks in advance
set is not used to assign values to regular variables; it is used to set the values of the positional parameters or to modify shell options. You need a regular assignment.
i=1
j=2
nombre="${i}_$j.txt"
echo "$i"
echo "$j"
echo "$nombre"
There is no need to declare variables prior to assignment; assignment creates a variable if necessary. The declare command is more about setting attributes on a name (-a, for instance, would mark the variable as an array variable, something you do not need here).
As an example of how set does work, consider
echo "First positional parameter: $1"
echo "Second positional parameter: $2"
set foo bar # $1=foo, $2=bar
echo "First positional parameter: $1"
echo "Second positional parameter: $2"
Does this code works as desired?
#!/bin/bash
i=1
j=2
echo $i
echo $j
nombre=$i"_"$j.txt
echo $nombre
#!/bin/bashor#!/usr/bin/env bashas your shebang, or#!/bin/shif you really wanted to write POSIX sh instead of bash (despite the question being tagged for the latter).#!/usr/binisn't a valid shebang, nor is# !usr/bin, and a script starting with either of those won't run correctly when started from something other than a shell.