custom sort method in jquery/javascript

Question

I want to sort a Array in custom way

Given arary:

arry = [0,0,1,1,2,2,3,3,4,4,5,5,6,6,7,7,8,8,9,9,10,10,11,11,12,12,13,13,14,14,15,15,16,16,17,17,18,18,21,21,22,22,23,23]

Expected output:

[21,22,22,23,23,0,0,1,1,2,2,3,3,4,4,5,5,6,6,7,7,8,8,9,9,10,10,11,11,12,12,13,13,14,14,15,15,16,16,17,17,18]

Use arr.sort(compareFunction) from developer.mozilla.org/en/docs/Web/JavaScript/Reference/… — Sangharsh
– Sangharsh, Commented Feb 24, 2017 at 10:21

Nina Scholz · Accepted Answer · 2017-02-24 10:21:54Z

9

You could check the value first and the sort number greater than 20 first.

var array = [0, 0, 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 11, 11, 12, 12, 13, 13, 14, 14, 15, 15, 16, 16, 17, 17, 18, 18, 21, 21, 22, 22, 23, 23],
    predicate = function (v) { return v > 20; };

array.sort(function(a, b) {
    return predicate(b) - predicate(a) || a - b;
});

console.log(array);

edited Feb 24, 2017 at 10:21

answered Feb 24, 2017 at 10:19

Nina Scholz

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1 Comment

Rajesh Dixit Over a year ago

You make coding look simple. #Respect

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