Transform multiple values from url to json in Django

Question

I have this URL:

http://example.com?variable=1&variable=2&a=text

I want to transform those values to JSON.

I have tried:

data = json.dumps(request.GET)

But I get {"variable": "2", "a": "text"}

It seems to work for single values but not for multiple ones.

How can I get all the values from the URL transformed?

Possible duplicate of URL query parameters to dict python

Jake Conway
– Jake Conway

2017-03-06 07:08:21 +00:00
Commented Mar 6, 2017 at 7:08 — Jake Conway
– Jake Conway, Commented Mar 6, 2017 at 7:08

Stephen Rauch · Accepted Answer · 2017-03-06 07:13:06Z

3

The urlparse module can do this for you.

Results:

from urlparse import urlparse, parse_qs

o = urlparse('http://example.com?variable=1&variable=2&a=text')
qs = parse_qs(o.query)
print(qs)

results:

{'variable': ['1', '2'], 'a': ['text']}

answered Mar 6, 2017 at 7:13

Stephen Rauch♦

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4 Comments

Adrian Martinez Over a year ago

For some reason I have this error(anaconda2/lib/python2.7/urlparse.py in urlsplit, line 182): 'function' object has no attribute 'find' So I can't try right now...Looking for a solution to that error.

Adrian Martinez Over a year ago

solved but i got this: {'a': ['1', "2'>>"], 'search_txt': ['T']}

Adrian Martinez Over a year ago

It seems to work. The reason why i got that result seems to be request.get_full_path. It wil return something like: <bound method WSGIRequest.get_full_path of <WSGIRequest: GET '?variable=1&variable=2&a=text'>> Note:I am using django

Adrian Martinez Over a year ago

Solved qs = parse_qs(request.META['QUERY_STRING']) data = json.dumps(qs) result: {"variable": ["1", "2"], "a": ["text"]}

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