java : create nested json object from String

Question

I want to create org.json.JSONObject from String. the String is "user.phone.num : 00113". the result that i would like to have is org.json.JSONObject object with this format:

{
user: 
     { 
       phone:  {num: 00113}
     }
}

so is there any built in method to achieve this result. Thanks.

Do you need org.json.JSONObject or maybe just simple String but in JSON format? — sf_
– sf_, Commented Jul 3, 2017 at 11:12
You may check this link - stackoverflow.com/questions/22042638/… — Razib
– Razib, Commented Jul 3, 2017 at 11:15
how would be your string if you have json like this {attr1:{attr2:'ebrahim'},att3:'ps'}? — Ebrahim Poursadeqi
– Ebrahim Poursadeqi, Commented Jul 3, 2017 at 11:25
@EbrahimPoursadeqi in this case i will have two String the first is attr1.attr2: ebrahim and the second is att3: ps . I build these json object , then i build the global json object — bacem ounis
– bacem ounis, Commented Jul 3, 2017 at 11:33

Ebrahim Poursadeqi · Accepted Answer · 2017-07-03 12:27:07Z

if every line of your json is splitted yo can try this code

import org.json.JSONException;
import org.json.JSONObject;

/**
 * Created by ebi on 7/3/17.
 */
public class Main {
    public static void main(String[] args) throws JSONException {

        String str = "user.phone.num : 00113";
        String json_str = str_to_json(str);
        JSONObject jsonObject = new JSONObject(json_str);
        System.out.println(jsonObject);
    }

    public static String str_to_json(String jsonByDot){
        int valOffset = jsonByDot.indexOf(":");
        String keys = jsonByDot.substring(0,valOffset).trim();
        String val = jsonByDot.substring(valOffset+1).trim();

        String keysArr[] = keys.split("\\.");
        String output = "";
        for(String key:keysArr){
            output+="{"+key+":";
        }
        output+=val;
        for (int i = 0 ;i<keysArr.length;i++){
            output+="}";
        }

        return  output;
    }
}

Darshit Chokshi · Accepted Answer · 2017-07-03 12:11:39Z

0

Try using below -

    JSONObject obj1 = new JSONObject();
        obj1.put("birthdate", "01-01-2017");
        obj1.put("age", new Integer(18));

   JSONObject obj2 = new JSONObject();
        obj2.put("name", "abc");
        obj2.put("details", obj1);

answered Jul 3, 2017 at 12:11

Darshit Chokshi

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