java regex find all whitespace in a string [duplicate]

I have see numerous suggestions for regex to find whitespace in a string none of which have worked so far. Yes the concept of looping through the string with a for next loop will work. I would really like to learn how to do this with regex and Pattern Matcher ! My question is what and where do I need to add to my regex string so it will return FALSE? code below I have added numerous incarnations of (\\s) to no avail. I do not want to remove the whitespace.

I tested the code suggested as a duplicate and it does not work see the link suggested in the comments

String tstr = "^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&])[A-Za-z\\d$@$!%*?&]";

String astr = etPW.getText().toString().trim();
Pattern regex = Pattern.compile(tstr);
Matcher regexMatcher = regex.matcher(astr);

boolean foundMatch = regexMatcher.find();

if(foundMatch == false){
    Toast.makeText( MainActivity.this, "Password must have one Numeric Value\n"
      + "\nOne Upper & Lower Case Letters\n"
      + "\nOne Special Character $ @ ! % * ? &", Toast.LENGTH_LONG ).show();
    //etPW.setText("");
    //etCPW.setText("");
    // Two lines of code above are optional
    // Also by design these fields can be set to input type Password in the XML file
    etPW.requestFocus();

    return ;
}