Accessing a function variable from another file in python [closed]

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I have two files File1 and File2. In File1 I have a function detect() defined as:

def detect():
    s = // some operations

I need to access this variable s in File2.

I have tried declaring the variable as global but it has not worked.

How can I access the variable without creating a class as in this post or by using __main__ as in this post ??

how about having the detect() function return the variable? — FlyingTeller
– FlyingTeller, Commented Feb 26, 2018 at 13:58
One way would be to have the detect function return the s value. Then you can call detect from anywhere. — John Gordon
– John Gordon, Commented Feb 26, 2018 at 13:58
I cannot call the function as it performs may other operations but I need to only access that variable. I'll need to call the function in order to access the variable which I don't want to. — Suraj Donthi
– Suraj Donthi, Commented Feb 26, 2018 at 14:00
Accessing a function's local variable without calling it doesn't make any sense. What's the X in this XY problem? — Aran-Fey
– Aran-Fey, Commented Feb 26, 2018 at 14:02
s doesn't have a value until detect() is actually evaluated, so what you're asking for doesn't make sense. — cowbert
– cowbert, Commented Feb 26, 2018 at 14:26

sahama · Accepted Answer · 2018-02-26 14:23:30Z

1

function detect must be run to init its local variables.

def detect():
    detect.tmp = 1

def b():
    print(detect.tmp)

detect()
b()

of course you can import one python file as python module and call its functions like

from File1 import detect
print(detect.tmp)

edited Feb 26, 2018 at 14:23

answered Feb 26, 2018 at 13:59

sahama

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