How can I check id in the array without using loop on the javascript?

Question

I try like this :

<script type="text/javascript">
    var clubs = [ 
        {id: 1, name : 'chelsea'},
        {id: 2, name : 'city'},
        {id: 3, name : 'liverpool'},
        {id: 4, name : 'manchester united'},
        {id: 5, name : 'arsenal'}
    ];
    var selectedId = 3;
    if(clubs.includes(selectedId))
        console.log('The selected id exist');
    else
        console.log('The selected id does not exist');
</script>

But it does not works. I only works if clubs array is array one dimensional

How can I solve it?

I want to do it with one statement. No loop

You can use some() method as suggested in your previous question a few minutes ago. — Mohammad Usman
– Mohammad Usman, Commented Apr 11, 2018 at 8:49
It doesn't work because there's no 3 in your clubs array. There's a {id: 3, name: 'liverpool'} object though. — Aaron
– Aaron, Commented Apr 11, 2018 at 8:52
Like @Aaron said, there's no 3 in your array. Javascript doesn't know that it should map 3 to id unless you tell it to do so as suggested by @Mohammed-Usman — H77
– H77, Commented Apr 11, 2018 at 8:57
Just wanted to point out: clubs array is one dimensional. It's an array of objects. — fdomn-m
– fdomn-m, Commented Apr 11, 2018 at 9:07

Hrishikesh · Accepted Answer · 2018-04-11 09:36:20Z

1

See if this helps.

var clubs = [{id: 1, name: 'chelsea'},
     {id: 2, name: 'city'},
     {id: 3, name: 'liverpool'},
     {id: 4, name: 'manchester united'},
     {id: 5, name: 'arsenal'}];

   var selectedId = 3;

   var exist = clubs.some(function(obj) { 
     return obj.id === selectedId;
   });

   if(exist) {
     console.log("Exist");
   }
   else{
     console.log("Not Exist");
   }

edited Apr 11, 2018 at 9:36

answered Apr 11, 2018 at 9:16

Hrishikesh

6323 silver badges13 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

bLuke · Accepted Answer · 2018-04-11 09:13:13Z

I think you have to loop if you want to keep your current structure. Anyway if you can make this little change i'd suggest to add the id as the key of the obj

var clubs = {
    4: {id: 1, name : 'chelsea'},
    3: {id: 3, name : 'city'},
};
var selectedId = 3;
if(selectedId in clubs) alert('yes')

as you can see from the example above, in this case an alert will display, cause it will find the obj with 3 as key.

var clubs = {
    4: {id: 1, name : 'city0'},
    8: {id: 8, name : 'city1'},
    9: {id: 9, name : 'city2'},
    10: {id: 10, name : 'city3'},
    11: {id: 11, name : 'city4'},
};
var selectedId = 3;
if(selectedId in clubs) alert('yes')

in this case, nothing will display cause there is no key 3

it's a possible solution if you can edit the structure of clubs.

RoboYak · Accepted Answer · 2018-04-11 09:15:04Z

0

You can solve this with .some() as Mohammad pointed out, but you need to pass it a function so that it can iterate through each object(some() and includes() are looping functions by the way):

https://jsfiddle.net/bdju9gLd/

var clubs = [ 
    {id: 1, name : 'chelsea'},
    {id: 2, name : 'city'},
    {id: 3, name : 'liverpool'},
    {id: 4, name : 'manchester united'},
    {id: 5, name : 'arsenal'}
];
var selectedId = 3;
if(clubs.some(function(obj) { return obj.id == selectedId; }))
    $("#text").text('The selected id exist');
else
    $("#text").text('The selected id does not exist');

edited Apr 11, 2018 at 9:15

answered Apr 11, 2018 at 9:09

RoboYak

1,4921 gold badge13 silver badges18 bronze badges

Collectives™ on Stack Overflow

How can I check id in the array without using loop on the javascript?

3 Answers 3

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related