I have tried to convert my array to a 2-D array and utilizing np.sort and np.lexsort but have not had any luck.
import numpy as np
# Here are the 2 arrays I would like to sort b using a.
a = np.array([6,5,3,4,1,2])
b = np.array(["x","y","z","a","b","c"])
Is it possible to sort b using a?
When printing b the output should be:
["b", "c", "z", "a", "y", "x"]
You can use the built-in NumPy indexing:
In [1]: import numpy as np
...:
...: # Here are the 2 arrays I would like to sort b using a.
...: a = np.array([6,5,3,4,1,2])
...: b = np.array(["x","y","z","a","b","c"])
In [2]: b[a - 1]
Out[2]: array(['c', 'b', 'z', 'a', 'x', 'y'], dtype='<U1')
Also, I think your desired output is c, b, z, a, y, x instead of b, c, z, a, y, x.
c, b, z, a, y, x instead of b, c, z, a, y, x." - you probably think that because you're thinking of the operation "take element result[i] from the index of b given by a[i]", while the questioner is thinking of the dual operation "put b[i] in the cell of result given by a[i]", or the operation "take the permutation that would sort a and apply that permutation to b". Those operations would produce b, c, z, a, y, x.
np.argsort?