from array import *
val=array('u',["thili","gfgfdg"])
print(val)
When I compiled above python code, the compiler showed an error.
What is the problem in my code.can not store strings in python array?
2 Answers
Firstly, the Python interpreter is written in C language language and that array library is includes array of C language (In fact, it is not array of Python, it is array of C). A string is array of chars in C (char is a number which act like one letter). You are passing two unicode strings as argument to the array function but one of these unicode strings is already an array for C. So you cant pass two unicode string to array function. Look at that:
from array import array
my_array = array("u","thili") # no error
print(my_array) # array('u', 'thili')
other_array = array("u",["thili","gfgfdg"])
Traceback (most recent call last):
File "<pyshell#5>", line 3, in <module>
my_array = array("u",["thili",""])
TypeError: array item must be unicode character
As you can see array of unicode string is not much different than normal unicode string. Because it contains only one string. You should use list or tuple class instead. And the list class in Python is array of Python.
my_list = ["thili","gfgfdg"] # same as: my_list = list("thili","gfgfdg")
my_tuple = ("thili","gfgfdg") # same as: my_tuple = tuple("thili","gfgfdg")
Dont forget that tuples are unmutable but lists are mutable. If you want to change value of any index, then use list. Tuples are good when you want to optimize your memory (RAM) usage. Finally tuples are more faster than lists in terms of creation.
4 Comments
juanpa.arrivillaga
" And list are more faster than tuples while indexing" No, they are not.
Ekrem Dinçel
Yes, they are (At least in my computer and python3.7). You can try it by using timeit module. Lists are a bit faster (But not slower). Try that: """ from timeit import timeit \na=list(range(100)) ; b=(range(100)) \ndef f(c): \n\tfor i in c: pass \nprint("List:",timeit(lambda: f(a))) ; print("Tuple:",timeit(lambda: f(b))) """
juanpa.arrivillaga
That compares iterating over a list versus iterating over a range object, not indexing, i.e.
my_sequence[0] between lists and tuplesEkrem Dinçel
Yes , i made an mistake. Thank you. But i am trying it with b=tuple(range(100)) and list is still faster. ???
You can not find anything faster or not by using timeit module in python or any programming language because time taken directly depends upon your machine configuration so for checking that thing we use time complexity in programming...
2 Comments
Joe Ferndz
I dont think the OP's question was about how fast tthe code will run. Please review the question again. This does not answer the question.
AngryParticle
This does not answer op's question.
arrayto hold characters (one string basically) but it is not intended to hold strings.list.val=array('u', 'thili gfgfdg').tounicode()Let me know if it works for you.