Creating array in PHP. Really need solution for the underling problem [duplicate]

Question

I have a string like below

 "\$tempArray['acct'][0]".$det["PATH"]

$det["PATH"] is an dynamically generated in each iteration. something like this "['e2']['2']['e2']['0']['e2']['0']"

I want an array to be defined like this

$tempArray['acct'][0]['e2']['2']['e2']['0']['e2']['0'] = array ();

Since $det["path"] changes in every iteration . I need this array to be created for in each iteration with the name

I have tried the below code . But it creates and array with $tmpArray. not like this $tempArray['acct'][0]['e2']['2']['e2']['0']['e2']['0']

 if(!is_array("\$tempArray['acct'][0]".$det["PATH"])){
   $tArray = "\$tempArray['acct'][0]".$det["PATH"];
   var_dump($tArray );
   $tArray = array();

Anonymous · Accepted Answer · 2019-11-27 04:08:32Z

1

The insecure way to do this is eval:

eval("\$tempArray['acct'][0]".$det["PATH"]." = array();");

The better way is to use the path as the key:

$tempArray['acct'][0][$det["PATH"]] = array();

answered Nov 27, 2019 at 4:08

Anonymous

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