How can I take multiple file as input in python & store in a variable

Question

I want to take multiple file as input from command-line like

#python script.py file1.txt file2.txt file3.txt .... file_N.txt

following program can take only one file as input

python script.py file1.txt

But I want to take multiple file as input.

    import sys
with open(sys.argv[1], 'r') as file:
    wordcount = file.read()
    words= wordcount.split()
    #print(words)
    count = {}
    for word in words:
        if word in count:
            count[word]=count[word] + 1
        else:
            count[word] = 1
    print(count)

Does this answer your question? Automatically open files given as command line arguments in Python — Błotosmętek
– Błotosmętek, Commented Apr 29, 2020 at 9:59

KORguy · Accepted Answer · 2020-04-29 09:58:42Z

0

They are stored in sys.argv. They are stored in array and you can access them through index.

a = str(sys.argv)
// a[0]: file1.txt
// ...

answered Apr 29, 2020 at 9:58

KORguy

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Jakob Guldberg Aaes · Accepted Answer · 2020-04-29 10:00:14Z

0

The sys module already contains all the arguments inside the sys.argv which is a list of all arguments passed to the program

The minimum working example I can come up with would be

import sys
names = sys.argv

This code generates a list of all arguments passed to the program. You could of course filter the input to make sure the names are valid.

answered Apr 29, 2020 at 10:00

Jakob Guldberg Aaes

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