Lambda function is outputting memory address instead of actual values [duplicate]

Question

when i run the code i get a memory location as an output

val = (lambda colmns:(colmns.max + colmns.min)/2
print(val)

You need to actually use the lambda. If you try to print it directly, you will get the address of where the lambda code lives in memory. — wkl
– wkl, Commented Jul 21, 2022 at 22:54
val is a function object, it isn't a "memory address", when you print a function object, that is how it is represented, just like any function, try def foo(): return 42 then print(foo) — juanpa.arrivillaga
– juanpa.arrivillaga, Commented Jul 21, 2022 at 23:05

tdelaney · Accepted Answer · 2022-07-21 22:57:27Z

0

A lambda is just an anonymous function object and that's why it prints that way. In fact, as soon as you assign it to a variable... then why have a lambda in the first place? Might as well do

def foo(colmns): 
    return (colmns.max + colmns.min)/2

And then it wouldn't be too surprising that print(foo) is <function 0x...>.

answered Jul 21, 2022 at 22:57

tdelaney

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tdelaney Over a year ago

@hghebrem - what are you talking about? The thing you seemed to have missed is that lambda creates a function object, and that's what I illustrated with the def. But I still needed to wrap that back specifically to the question about where "<function at 0x00000200FF8A5E50>" comes from. When you see it as a def I didn't think there would be any question about why is printed as a "function".

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