Argument's name shadows keyword in module argparse python [duplicate]

Question

When I try to get argument with flag "--from" from argparse.ArgumentParser.parse_args() an error occurs. IDE says that "from" is import statement and the code is unreachable:

parser = argparse.ArgumentParser(prog='cache_wiki.py',
                                     description='Find shortest path between links')
parser.add_argument('--from', required=True, help='page to start search with')
args = parser.parse_args()
print(args.from)

It is ok with another name:

parser = argparse.ArgumentParser(prog='cache_wiki.py',
                                     description='Find shortest path between links')
parser.add_argument('--f', required=True, help='page to start search with')
args = parser.parse_args()
print(args.f)

but I really need to use flag "--from".

docs.python.org/3/library/argparse.html#dest

jonrsharpe
– jonrsharpe

2023-02-05 18:47:07 +00:00
Commented Feb 5, 2023 at 18:47 — jonrsharpe
– jonrsharpe, Commented Feb 5, 2023 at 18:47
The code isn't unreachable; args.from is a syntax error.

chepner
– chepner

2023-02-05 18:51:50 +00:00
Commented Feb 5, 2023 at 18:51 — chepner
– chepner, Commented Feb 5, 2023 at 18:51

chepner · Accepted Answer · 2023-02-05 18:50:59Z

3

I would ignore the IDE here. True, you cannot use args.from, but that's just a syntactic limitation. You can still access the attribute using, for example, getattr(args, 'from').

You can also override the default destination name so that you can use the option --from, but set a different attribute:

...
parser.add_argument('--from',
                    required=True,
                    dest='from_',
                    help='page to start search with')

args = p.parse_args(['--from', 'foo'])
assert args.from_ == 'foo'

answered Feb 5, 2023 at 18:50

chepner

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