Possible Duplicate:
Converting binary to decimal without using loop
I'm looking for the simplest and fastest solution. I tried documentation but could find anything.
I have an array of bits like [0, 1, 1, 1] and I want to convert it to simple int number 7. I get this array with bitget(x, 1:3), where x is an integer.
Just as a pedagogical alternative to @Edwin and @Azim's solution's (which are better for production), try
b = [1 0 0 1]; % or whatever
sum(b.*(2.^[length(b)-1 : -1 : 0])) % => 9 for the above
We create the basis elements with 2.^[length(b)-1 : -1 : 0] = [8 4 2 1], multiply each element by the binary value to get [8 0 0 1], then sum to get the final answer.
@Edwin's answer uses binvec2dec which is part of the Data Acquisition Toolbox. This toobox is an additional toolbox (developed by Mathworks) but not part of the base MATLAB package.
Here is a solution that does not depend on this toolbox.
Use num2str to convert the binary array to a string
str=num2str(bin_vec);
use bin2dec to get decimal value
dec_num=bin2dec(str);
A little rusty on Matlab, but this should work.
% This assumes you're using a vector of dimension 1 x n (i.e. horizontal vector)
% Otherwise, use flipud instead of fliplr
function [dec_num] = convert(bin_vec)
bin_vec = fliplr(bin_vec);
dec_num = binvec2dec(bin_vec);
% EDIT: This should still work
num = convert(bitget(x, 1:3);
For future reference, if this is about homework, use the homework tag.
binvec2dec Documentation
fliplr Documentation
flipud Documentation
