pulseIn() function not working

pulseIn() returns an unsigned long (32 bits) not an int (16 bits), so you may have some truncation occurring in your program leading to a 0 value.

Hence you should modify your program as follows:

int pulsepin = 8;
unsigned long value = 0;

void setup() 
{
  pinMode(pulsepin, INPUT); 
  Serial.begin(9600);
}

void loop()
{
  value = pulseIn(pulsepin, HIGH);
  Serial.println(value);
  delay(1000);
}

Also beware that pulseIn() has a timeout (it will not wait forever). This timeout is used for the whole completion of the pulse, i.e. first waiting for the signal to get HIGH, then waiting for it to get back LOW. If no pulse is detected and complete (LOW -> HIGH -> LOW) within this time, then pulseIn() will return 0.

Default timeout value is 1 second, but you can set any value (in microseconds) you want that can hold in an unsigned long:

e.g. if you need 10 seconds, then:

  value = pulseIn(pulsepin, HIGH, 10000000UL);

I am not sure why you use delay(1000) in your loop(), I would remove it as a pulse may occur during that time and it would not be seen by your program.

Here is a suggested update (I also used const where it made sense but that won't change program behavior):

const unsigned long PULSEIN_TIMEOUT = 10000000UL;
const int pulsepin = 8;
unsigned long value = 0;

void setup() 
{
  pinMode(pulsepin, INPUT); 
  Serial.begin(9600);
}

void loop()
{
  value = pulseIn(pulsepin, HIGH, PULSEIN_TIMEOUT);
  Serial.println(value);
}

You may also want to avoid printing 0 values since they mean no pulse was detected:

void loop()
{
  value = pulseIn(pulsepin, HIGH, PULSEIN_TIMEOUT);
  if (value > 0)
    Serial.println(value);
}