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I have this number returned from an Ajax request: 015-0011-00001. I want to increment the last part of the number (00001) on document load. What I did was get the last number and increment it then combine the numbers again. Is there a cleaner way of incrementing this number without slicing the number into many parts?

DEMO

var data = [{"code":"456100010011","incrementingnumber":"015-0011-00001"}];

var code = data[0].code;
var inc = data[0].incrementingnumber;
var res = code.slice(-4);
var inc1 = inc.slice(-4);
//alert(inc1);
var inc2 = parseInt(inc1) + 1;

var incrementvalue = ("00000" + inc2).slice(-5); // -> result: "0001"

console.log("015-" + res + "-" + incrementvalue);
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2 Answers 2

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var data = [{"code":"456100010011","incrementingnumber":"015-0011-00001"}];

var code = data[0].code,
    inc = data[0].incrementingnumber;
var inc1 = inc.split('-');
inc1[2] = ('00000' + ++inc1[2]).slice(-5);

document.write(inc1.join('-'));

You don't need the code.slice, but you'd still need to split your incrementingnumber value.

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  • \$\begingroup\$ Let me ask one thing when you join the segments the previous value of element in index 2 will be replace automatically when you declare that in line segments[2] = ("00000" + (+segments[2] + 1)).slice(-5); . I just want to understand what happened. thank you for making cleaner than before. \$\endgroup\$ Commented Sep 22, 2015 at 2:29
  • \$\begingroup\$ ++inc1[2] will increment the value at the 3rd index of inc1 array. Since .split splits the string to an array; you have inc1 = [[0] = '015', [1] = '0011', [2] = '00001']. On increment, the preceeding 0s get removed as the tpe changes from string to number. To format it back with 0-padding; we use slice. You can also use .substring instead of slice. \$\endgroup\$ Commented Sep 22, 2015 at 4:44
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Here's another approach

var data = [{"code":"456100010011","incrementingnumber":"015-0011-00001"}];

var segments = data[0].incrementingnumber.split('-');
segments[2] = ("00000" + (+segments[2] + 1)).slice(-5);

document.write(segments.join('-'));

With very little context to go by, the last 4 digits of code appear to be the same as the second segment of incrementingnumber. I could very well assume they're the same, thus omitting code from being sliced.

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  • \$\begingroup\$ Let me ask one thing when you join the segments the previous value of element in index 2 will be replace automatically when you declare that in line segments[2] = ("00000" + (+segments[2] + 1)).slice(-5); . I just want to understand what happened. thank you for making cleaner than before. \$\endgroup\$ Commented Sep 22, 2015 at 2:29
  • \$\begingroup\$ @Pekka Yes. The result of ("00000" + (+segments[2] + 1)).slice(-5) will be assigned to segments[2]. \$\endgroup\$ Commented Sep 22, 2015 at 12:04

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