How can I get default display form url of sharepoint list item via Rest or JSOM. I found the result by link: How to get the Display Form URL, using REST
But the XML returns all of the display form url, I don't know how to specify where is the default URL?
I need to get it dynamically!
You could also use
_api/Web/Lists/GetByTitle('List title')/DefaultDisplayFormUrl
If you want for all lists do
_api/Web/Lists?$select=DefaultDisplayFormUrl
Note that the property is not visible when visiting List directly, need full path or $select.
data.value. It could alter if you use SPO, on premise or through an app. What you can do is to call console.log(data) and you will see the object structure in say Chrome dev tools. Another option is to view it in Dev tools network tab. Yet another is to set break point and inspect data variable.
console.log(data) work perfect then I can inspect the object. Great!
Use DefaultDisplayFormUrl at the time of loading the list in Javacript client object model. Example:
var clientContext = new SP.ClientContext.get_current();
var list = clientContext.get_web().get_lists().getByTitle(listTitle);
clientContext.load(list, 'DefaultDisplayFormUrl');
Then while enumerating the listitemcollection use get_defaultDisplayFormUrl() to create the Url. Example:
while (listItemEnumerator.moveNext()) {
var listItem = listItemEnumerator.get_current();
var listItemId = listItem.get_item('ID');
var href = list.get_defaultDisplayFormUrl() + "?ID=" + listItemId;
}
