How to get data-href instead of href with selenium in python?

Question

I have currently a python code that should grab a link from google. However, google uses a somewhat different method to linking. how could I grab the data-href instead of just href.

this is the html example of a google link, the code is different when I use firefox.. there is no data-href:

<a 
 href="/url?    sa=t&amp;rct=j&amp;q=&amp;esrc=s&amp;source=web&amp;cd=2&amp;cad=rja&amp;uact=8&amp;ved=0CC0QFjAB&amp;url=http%3A%2F%2Fwww.dongemondcollege.nl%2F&amp;ei=ihIwVdTqKtDYaoSjgMAP&amp;usg=AFQjCNEvpxj60GxhQekQ2qI6QXDP2Vso1g&amp;sig2=DuKoiCbIcI0ncx8D4gnSaA&amp;bvm=bv.91071109,d.bGQ"
 onmousedown="return rwt(this,'','','','2','AFQjCNEvpxj60GxhQekQ2qI6QXDP2Vso1g','DuKoiCbIcI0ncx8D4gnSaA','0CC0QFjAB','','',event)"
 data-href="http://www.dongemondcollege.nl/">
 Dongemond College &gt; Algemeen &gt; Home
</a>

Below is the Python code that should grab the link

Any suggestions?

def getLinks(source):

    websiteLinks = []
    for link in source.find_all('a'):
        url = link.get('href')
        if url:
            if '/search?' not in url:
                websiteLinks.append(url)
    return websiteLinks

Dongemond College > Algemeen &gt how to get this value??? i mean i want to print this value...also assume this value keep changing. — niharika gaur
– niharika gaur, Commented Jan 25, 2018 at 12:52

Community · Accepted Answer · 2017-05-23 12:41:32Z

3

data-href is an attribute of a HTML tag, try to use get_attribute method, something like:

url = browser.find_element_by_xpath("//a").get_attribute("data-href")

For more information see: http://selenium-python.readthedocs.org/en/latest/api.html#selenium.webdriver.remote.webelement.WebElement.get_attribute

Or this for examples: https://stackoverflow.com/questions/12579061/python-selenium-find-object-attributes-using-xpath

edited May 23, 2017 at 12:41

CommunityBot

1

answered Apr 17, 2015 at 8:11

Niels van Reijmersdal

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IAmMilinPatel · Accepted Answer · 2020-07-21 02:49:05Z

0

This works

botonAceptar = driver.find_element_by_xpath('//a[@id="close_entrance_terms"]').click()

edited Jul 21, 2020 at 2:49

IAmMilinPatel

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answered Jul 21, 2020 at 1:59

Jorge Gonzalez

1

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