$tally['zero']['status']='hello';
echo $tally['zero']['status'];
//prints hello, this is expected
In this example, why is only the first letter being printed?
$tally = array( "zero" => '0');
$tally['zero']['status']='hello';
echo $tally['zero']['status'];
// prints h, I was expecting hello
In this example, why is an error being thrown?
$tally['zero'] = 0;
$tally['zero']['status']='hello';
echo $tally['zero']['status'];
//prints Warning: Cannot use a scalar value as an array
In this example, why is only the first letter being printed?
$tally = array( "zero" => '0'); $tally['zero']['status'] = 'hello'; echo $tally['zero']['status']; // h
In PHP, strings can be indexed like arrays, and can also be modified in place. So 'status' becomes 0 when indexing the string, and the first character of hello is assigned to the first letter of $tally['zero']. For example, this:
$tally = array( "zero" => '01');
$tally['zero']['status'] = 'hello';
echo $tally['zero'];
Would print "h1".
In this example, why is an error being thrown?
$tally['zero'] = 0; $tally['zero']['status'] = 'hello'; echo $tally['zero']['status'];
Like the error says, 0 is not an array. You can't index it, hence the warning.
E_WARNING in the situation you described, guiding the dev closer to the problem.be careful about using " and '. While using " content can be interpreted as a varaible value.
0 != '0' number/string
I think that all mystery is hidden here.
