PHP: Array declaration issue

Question

I want to declare about 100 arrays, like $game1_array, $game2_array ... $game100_array and use them in a calculation. Can I use some sort of look, going from 1 to 100 and declare these in 4 lines rather than declaring them independently?

I tried the following but it didn't work:

for ($i = 1; $i <= 100; $i++) {
$game.'$i'._array = array();
}

Please point out the error.

Why don't you use array of arrays instead? $game1_array , $game2_array is a really bad design decision — zerkms
– zerkms, Commented Nov 8, 2013 at 10:37

zerkms · Accepted Answer · 2013-11-08 10:38:36Z

5

What you're trying to accomplish is a poor design decision. It's much better to create an array which holds 100 nested arrays.

It could be done with such code:

$games = array_fill(0, 100, array());

Then you can work with them like:

$games[42][] = 'foo'; // would append a 'foo' item into 43rd array

answered Nov 8, 2013 at 10:38

zerkms

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2 Comments

nice ass Over a year ago

If the array is numerically indexed and you know the array size, it's probably a better idea to use splFixedArrays

zerkms Over a year ago

@onetrickpony: indeed, but probably it would be too much for a total newbie :-)

gherkins · Accepted Answer · 2013-11-08 10:36:49Z

4

for($i=1;$i<=100;$i++)
{
    ${'game'.$i.'_array'} = array();
}

var_dump( $game2_array );

see http://php.net/manual/en/language.variables.variable.php

answered Nov 8, 2013 at 10:36

gherkins

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2 Comments

zerkms Over a year ago

Could upvoters comment why do you do that? I agree this answer directly answers the question, but don't you think that the major difference between SO and yahoo answers is that we can think here, and that our mission here is to teach people not just blindly give them examples of crappy code?

gherkins Over a year ago

see, i think pointing out errors in a taken approach is as much part of "the mission" as showing a potentially better one is ... +1 for your answer though ;)

rebe100x · Accepted Answer · 2013-11-08 10:39:41Z

1

for($i=1;$i<=100;$i++){
 $gameArray[$i] = array();
}

answered Nov 8, 2013 at 10:39

rebe100x

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