Using in_array() in PHP

Question

I am trying to display menus and give user rights to my users based on database value using Codeigniter. But its not working, may be the problem is in the view file. I have the following table.

Table Name: module_permission

   id   user_id   delete     add    edit
   1       1        0         1      1

My Controller:

$this->load->model('mod_module_permission');
$data['permit']= $this->mod_module_permission->permission($user_id);

My Model:

  $this->db->select('*');
    $this->db->from('module_permission');
    $this->db->where('user_id', $user_id);                                          
    $getData = $this->db->get('');
    if($getData->num_rows() > 0)
    return $getData->result_array();
    else
return null;

My View :

    if ( in_array(add=>'1',$permit)) {echo "YES";} else {echo "NO";}

Could you please tell me what change in the view file could make the problem solved?

Thanks :)

If add=>'1' is supposed to be an array, use array(add=>'1') — dpk2442
– dpk2442, Commented Jun 1, 2012 at 15:59
1. Read the docs on in_array(). 2. I don't think you want in_array(), I think you want to say if (isset($permit['add']) && $permit['add'] == 1) { ... } — nachito
– nachito, Commented Jun 1, 2012 at 16:01

Michael Zelensky · Accepted Answer · 2012-06-01 16:33:33Z

2

obviously, the problem is with in_array() function usage

check the in_array() manual:

bool in_array ( mixed $needle , array $haystack [, bool $strict = FALSE ] )

The first parameter should be string or whatever, and the second parameter is an array being searched through.

Besides, in the first parameter you are wrongly trying to define an array, the array structure block should be similar to that:

array('key'=> 'value')

(strings are in colons)

Try this:

echo $tmp = ($permit == '1') ?  "YES" : "NO";

or

$arr = array('key'=>'1');
echo $tmp = (in_array($permit, $arr)) ?  "YES" : "NO";

edited Jun 1, 2012 at 16:33

answered Jun 1, 2012 at 15:59

Michael Zelensky

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Comments

WWW · Accepted Answer · 2012-06-01 16:00:31Z

1

You are using in_array() incorrectly. It's in_array($needle, $haystack) where $needle is a single variable of some type. You should try in_array('1', $permit) (if $permit is actually an array).

The above answer only applies if in_array() is the appropriate solution to your problem, of course.

answered Jun 1, 2012 at 16:00

WWW

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Comments

black_belt · Accepted Answer · 2012-06-01 17:55:43Z

0

I think you could use the following method:

 <?php foreach ($permit as $rows){ 
    if ($rows['add']==1) {echo "YES";} else {echo "NO";}
} ?>

answered Jun 1, 2012 at 17:55

black_belt

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Comments

Donovan · Accepted Answer · 2012-06-01 21:20:00Z

Looking at you're question. It seems that you're not sure what result_array() returns. In your case, it will return the following:

array (
    array (
        "id" => 1,
        "user_id" => 1,
        "delete" => 1,
        "add" => 1,
        "edit" => 1
    )
)

So when you try to do an in_array() you are looking at the outer most array and you're if statement will never pass. However, the simple fix for your problem would be to change you're Model and update this line from:

return $getData->result_array();

to

return $getData->result_array()->row();

Then in you're view change this line:

if ( in_array(add=>'1',$permit)) {echo "YES";} else {echo "NO";}

to

if ($permit->add == 1) {echo "YES";} else {echo "NO";}

That is just one way to work with you're code to get the results you want.

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