How to use function in_array with CodeIgneter

Question

I am trying to use the PHP function in_array within a view using CodeIgneter.

This is the method

class User_details extends CI_Model {

public function checkID(){
$query = $this->db->query("SELECT id FROM users");

return $query->result_array();

}

This is the controller

$this->load->model('user_details');

$data['allUserID'] = $this->user_details->checkID();
$this->load->view('user_details/content',$data);

This is the script I am trying to use in the view

$id = $this->uri->segment(4);//user's id for example: 218


if(in_array($id,$allUserID)){
echo 'exists';
} else {
echo 'does not exist';
}

Unfortunately he script does not work as expected.

If I check the array using print_r($allUserID) I get following result:

Array ( [0] => Array ( [id] => 217 ) [1] => Array ( [id] => 218 ...
...and so on...

Last week I started learning CodeIgneter and I did not understand its approach yet.

there is nothing related to codeigneter and in_array its a php function used to find something in array. you are using it in a wrong way. it is used for single dimensional array — Ravi Kant Mishra
– Ravi Kant Mishra, Commented Apr 1, 2015 at 13:47

Shravan Sharma · Accepted Answer · 2015-04-01 13:53:37Z

2

in_array() accept single dimensional array and you are passing two dimensional array. Try converting it to single dimensional array like

$array = array_map('current', $allUserID);

if(in_array($id, $array)){
 echo 'exists';
} else {
  echo 'does not exist';
}

answered Apr 1, 2015 at 13:53

Shravan Sharma

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1 Comment

Thanks to all of you. Yes, sure: I was using in_array() in a wrong way.