How to set variable in preg_replace (html syntax)?

Question

$con = preg_replace('#(<input type="text"[^>]+?>)#', '<input type="hidden" name="dog" value="$a">${1}', $content);

How to set value as variable? This what I've got is not correct ($a, syntax?)

Waygood · Accepted Answer · 2012-06-29 11:23:01Z

1

do you need $a or the contents of the variable $a

'<input type="hidden" name="dog" value="'.$a.'">${1}'

answered Jun 29, 2012 at 11:23

Waygood

2,6832 gold badges17 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Jack Bliss · Accepted Answer · 2012-06-29 11:14:31Z

1

Instead of ${1}, I think it should just be $1. That's what I always use and it seems to work.

answered Jun 29, 2012 at 11:14

Jack Bliss

1146 bronze badges

${1} - it work. I will add $a as value -> <input type="hidden" value="$a"> - this is not correct.