dynamic variables in preg_replace in PHP

Question

I have a text template like this:

$template = [FIRSTNAME] say hello to [NAME]

I have an user array like

[user_name] => myname
[user_firstname] => myfirstname

and I would like to transform it with preg_replace so I tried this:

$replacement = '$user[user_${1}]';
$result['texte'] = preg_replace('/[(.*)]/', {$replacement}, $result['texte']);

without any success :(

also, you'll need to escape the square brackets in your regex. otherwise you'll match only one character out of (, ., *, ). — Martin Ender
– Martin Ender, Commented Jun 25, 2013 at 23:27

Explosion Pills · Accepted Answer · 2013-06-25 23:30:43Z

5

/[(.*)]/ does not escape the [ or ], and would match essentially everything if it did. Use /\[(.*?)\]/. Additionally, you need to strtolower the matched inner value.

$template = "[FIRSTNAME] say hello to [NAME]";
$replacements = array(
   'user_name' => 'myname',
   'user_firstname' => 'myfirstname',
);

$result['texte'] = preg_replace_callback('/\[(.*?)\]/', function ($match)
    use ($replacements) {
    return $replacements["user_" . strtolower($match[1])];
}, $template)

answered Jun 25, 2013 at 23:30

Explosion Pills

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1 Comment

Klaitos Over a year ago

Works very well ! Thanks for the tips about regex and []

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