Bash array variable from loop

Question

I would like to store a variable ($random) from the loop statement - currently only the last statement from the loop is printed. Please note that I would like to use this variables outside of the loop.

#!/usr/bin/env bash

for backup in $(s3cmd ls s3://bucket/ | awk '{ print $2 }')
do
latest=$(s3cmd ls $backup | awk '{ print $2 }'  | sed -n '$p')
random=$(s3cmd ls $latest | shuf | awk '{ print $4 }' | sed -n '1p')
        s3cmd get $random $data_dir >/dev/null 2>&1
done

echo "$random

chepner · Accepted Answer · 2012-08-20 13:50:22Z

1

It's not entirely clear what you are asking, but I think you are saying you want to keep a record of each value $random receives during execution of the loop.

declare -a randoms

for backup in $(s3cmd ls s3://bucket/ | awk '{ print $2 }')
do
latest=$(s3cmd ls $backup | awk '{ print $2 }'  | sed -n '$p')
random=$(s3cmd ls $latest | shuf | awk '{ print $4 }' | sed -n '1p')
        s3cmd get $random $data_dir >/dev/null 2>&1
randoms+=( $random )
done

echo ${randoms[@]}

answered Aug 20, 2012 at 13:50

chepner

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