My bash script call a php file
#!/bin/bash
data=$(./getconfig.php)
The file getconfig.php is:
#!/usr/bin/env php
<?php
$array = array();
...
How can I return the $array from the php file in order to manipulate this array in the bash script?
As per documentation, an array is initialized with the following syntax:
farm_hosts=(web03 web04 web05 web06 web07)
So all you need to do is implode your $array:
echo implode(' ', $array);
You can use the =() format to read lines into an array like this
data = (`./getconfig.php`)
You would just need to make sure your PHP script output one line for each item in the array or there is a space between each item.
The key here is using backticks to get the replacement value from PHP script output.
