Pass shell variables as arguments to PHP script

Question

I want to pass shell variables to a PHP script. This is my attempt:

var1=`echo name_16`
var2=`echo /home/place/end/name_16`
php script.php ${var1} ${var2}

These variables contain special characters [)(*&^%$#@!~<>_] but no hyphens.

I am running PHP 4.3.9 cgi.

I attempt to pick up the variables in my PHP script thus:

    $fish = $argv[1];
    $sticks = $argv[2];

These variables come up as null. I've tried var_dump($argv); and this returns null as well.
Am I passing these parameters correctly or am I missing something here?

From: stackoverflow.com/questions/7803025/… Try $_SERVER['argv'] — Halcyon
– Halcyon, Commented Feb 12, 2014 at 16:59
Exactly what do your parameters look like? Examples? I did a quick check with a simple alphabetic param and had no problem. — lurker
– lurker, Commented Feb 12, 2014 at 17:04
Post an actual example of how you're calling this script with the variables — ElefantPhace
– ElefantPhace, Commented Feb 12, 2014 at 17:05
the example is exactly how I am calling the script from within a .sh script. — eddiecubed
– eddiecubed, Commented Feb 12, 2014 at 17:08
So you're defining your variables after you call script.php? — ElefantPhace
– ElefantPhace, Commented Feb 12, 2014 at 17:10

lurker · Accepted Answer · 2014-02-12 21:17:46Z

1

I wanted to add this as a comment, but need the formatting ability of an answer to respond.

There's something else wrong with the code. A basic test of arguments shows that the variables should work.

Contents of foo.php:

<?php
    print "$argv[1]\n$argv[2]\n" ;

    $x = $argv[1];
    $y = $argv[2];

    print "$x\n$y\n";
?>

Then the setup:

$ var1=`echo name_16`
$ var2=`echo /home/place/end/name_16`

And execution:

$ php foo.php ${var1} ${var2}
name_16
/home/place/end/name_16
name_16
/home/place/end/name_16
$

So the problem is not reproducible using the information provided. The above is run with PHP 5.2.6 (cli) (built: May 8 2008 08:53:44), so it is, perhaps, a difference in version behavior.

edited Feb 12, 2014 at 21:17

answered Feb 12, 2014 at 18:02

lurker

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5 Comments

eddiecubed Over a year ago

i figured it would be the version. possibly that I don't have access to cli.

lurker Over a year ago

@eddiecubed could you try the same simple test that I did above and see what happens, just to be sure we're apples-to-apples?

eddiecubed Over a year ago

I get nulls for output. The problem here is the version. The variable register_argc_argv is set to false. Which means the argv never gets built. So i need to look into using a different way of sending these variables over.

lurker Over a year ago

@eddiecubed thanks for trying the specific experiment; I agree with your conclusion.

eddiecubed Over a year ago

thanks for being helpful. I decided to just go with writing the variables to a text file in sh and then read the file within php. This worked.

Dima · Accepted Answer · 2014-02-12 17:06:11Z

0

just use $argv, its an array of arguments and quotes around special args.

http://www.php.net/manual/en/reserved.variables.argv.php

test.php:

<?php
  print_r($argv);
?>


>HHH="&^%$#@"
> php test.php hello args $HHH

output:

Array
(
[0] => test.php
[1] => hello
[2] => args
[3] => &^%$#@

)

edited Feb 12, 2014 at 17:06

answered Feb 12, 2014 at 17:00

Dima

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3 Comments

eddiecubed Over a year ago

I've tried this and it comes up with nothing. I've tried var_dump and I come up with null.

Dima Over a year ago

i just ran it and it worked. did you put quotes around the special args?

eddiecubed Over a year ago

I've tried your test verbatim and I get empty output.

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